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C, poredak brojeva
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skyy
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Post: #1
C, poredak brojeva

Ovako ako netko ima vremena trebao bih da zadatak sadrzava to da na pocetku pita koliko brojeva hocemo unjeti i da zatim mozemo unjeti toliko brojeva i da poslije ispise od najveceg do najmanjeg te brojeve koje smo unijeli, ako netko moze bio bih mu zahvalan

10-06-2008 03:03 PM
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Len0
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Post: #2
RE: C, poredak brojeva

Evo ti u C++, pa "prevedi" sebi u C.

Code:
#include<iostream>
using namespace std;
int main(){
int br_clanova;
cout<<"Koliko brojeva zelite unijeti: ";
cin>>br_clanova;
int *brnz=new int[br_clanova];
for(int i=0; i<br_clanova;i++){
cout<<"Unestire "<<i+1<<" broj: ";
cin>>brnz[i];
}

cout<<endl<<endl;
for(int i=0; i<br_clanova;i++){
for(int j=i;j<br_clanova;j++){
if(brnz[i]<brnz[j]){swap(brnz[i],brnz[j]);}
}}
for(int i=0;i<br_clanova;i++){
cout<<brnz[i]<<", ";}
cout<<endl<<endl;
system("pause");
return 0;
}


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10-06-2008 06:47 PM
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skyy
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Post: #3
RE: C, poredak brojeva

ajd molim vas ako netko moze ovo prevesti ili zna neki program / web da se to moze prevest jer C++ neznam ni malo

11-06-2008 12:10 AM
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Puž
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Post: #4
RE: C, poredak brojeva

Code:
#include<stdio.h>

int main()
{
    int br_clanova;
    
    printf("Koliko brojeva zelite unijeti: ");
    scanf("%d",&br_clanova);

    int *brnz=new int[br_clanova];
    for(int i=0; i<br_clanova;i++)
    {
        printf("Unesite %d broj: ",i+1,".");
        scanf("%d",&brnz[i]);
    }
    
    for(int i=0; i<br_clanova;i++)
    {
        for(int j=i;j<br_clanova;j++)
        {
            if(brnz[i]<brnz[j])
            {
                brnz[i]+=brnz[j];
                brnz[j]=brnz[i]-brnz[j];
                brnz[i]-=brnz[j];
            }
        }
    }
    for(int i=0;i<br_clanova;i++)
    {
        printf("%d \n",brnz[i]);
    }
    
    return 0;
}


Ovo sam ti sklpeo na poslu, a tu neam c kompajler. Trebalo bi radit.

12-06-2008 10:40 AM
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skyy
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Post: #5
RE: C, poredak brojeva

hvala, imalo je nkih malih greskica pa sam prepravio. jeli se moze ikako napravit da mogu biti realni brojevi, ja sam probao i nisam mogo nikako?

12-06-2008 10:51 AM
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Lord Gewicht
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Post: #6
RE: C, poredak brojeva

1. Isuse! Pa ovo je nevjerojatno koji je ovo ljigavac! Sve da mu se rijesi... I jos ovo, i jos ono...
2. ovo sto je puž napisao nije C kod! C nema new operator, u C-u sve moras deklarirati na pocetku funkcije
3. Ljigavac, evo ti! Pocmi raditi sam! Ako imas ikakvo programiranje i bar si u srednjoj skoli ovo MORAS ZNATI!

Code:
#include<stdio.h>
#include<malloc.h>//ako dinamicki alociramo
int main()
{
    int br_clanova,i,j;
    //float brnz[1000]; //STATICKA alokacija
    float *brnz;
    
    printf("Koliko brojeva zelite unijeti: ");
    scanf("%d",&br_clanova);

    brnz = ( float * )malloc( sizof(float) * br_clanova );//dinamicka alokacija
    for(i=0; i<br_clanova;i++)
    {
        printf("Unesite %d broj: ",i+1);
        scanf("%d",&brnz[i]);
    }
    
    for(i=0; i<br_clanova;i++)
    {
        for(j=i;j<br_clanova;j++)
        {
            if(brnz[i]<brnz[j])
            {
                brnz[i]+=brnz[j];
                brnz[j]=brnz[i]-brnz[j];
                brnz[i]-=brnz[j];
            }
        }
    }
    for(i=0;i<br_clanova;i++)
    {
        printf("%d \n",brnz[i]);
    }
    
    return 0;
}

12-06-2008 12:59 PM
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Gogy
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Post: #7
RE: C, poredak brojeva

Lord Gewicht, imaš opomenu!


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12-06-2008 01:18 PM
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Lord Gewicht
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Post: #8
RE: C, poredak brojeva

Zahvaljujem na reputaciji -1! Vidim da ni hvala ne mozes dobiti(a kamoli da ti neko da pozitivni stav), ili je to neki sick nacin za reci hvala! Pozdrav nezahvalniku!

17-06-2008 12:16 AM
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hurmash1ca
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Post: #9
RE: C, poredak brojeva

Rep -1 si dobio jer si drugom korisniku rekao da je ljigavac.


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17-06-2008 12:38 AM
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Gogy
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Post: #10
RE: C, poredak brojeva

Od skyya stvarno nije uredu što se više nije vratio i zahvalio. U njegovo ime ću ti dat +1 jer si se potrudio napisat kod. Al' molim te ubuduće pazi kak se izražavaš i sve će biti ok.


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17-06-2008 03:04 PM
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